d=-6d^2+102d+96

Solution for d=-6d^2+102d+96 equation:

d=-6d^2+102d+96

We move all terms to the left:

d-(-6d^2+102d+96)=0

We get rid of parentheses

6d^2-102d+d-96=0

We add all the numbers together, and all the variables

6d^2-101d-96=0

a = 6; b = -101; c = -96;
Δ = b2-4ac
Δ = -1012-4·6·(-96)
Δ = 12505
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-101)-\sqrt{12505}}{2*6}=\frac{101-\sqrt{12505}}{12}
$
$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-101)+\sqrt{12505}}{2*6}=\frac{101+\sqrt{12505}}{12}
$